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Chemistry: Enzymes & cardiac markers – page 6

132 Chemistry MCQs on Enzymes & cardiac markers with answers and explanations.

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Q101MediumEnzymes & cardiac markers

What is the ESC-recommended NT-proBNP rule-out cut-off for acute heart failure in a breathless patient in the emergency department?

Answer: A. 300 pg/mL

An NT-proBNP below 300 pg/mL makes acute heart failure unlikely. Higher, age-related values (450, 900, 1800 pg/mL) are used to rule in. The non-acute rule-out value is lower, 125 pg/mL.

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Q102MediumEnzymes & cardiac markers

A non-drinker on long-term phenytoin has GGT 150 U/L with normal ALT, ALP and bilirubin. The most likely explanation is:

Answer: B. Hepatic enzyme induction by the drug

Phenytoin and other enzyme-inducing drugs increase hepatic GGT synthesis without liver damage, so an isolated GGT rise is common. Biliary obstruction would also raise ALP.

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Q103MediumEnzymes & cardiac markers

Amylase measured on EDTA plasma gives a falsely low result because amylase requires:

Answer: D. Calcium

Amylase is a calcium-containing metalloenzyme (also activated by chloride). EDTA and citrate chelate calcium and inhibit it, so serum or heparin plasma should be used.

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Q104MediumEnzymes & cardiac markers

A farmer has miosis, heavy salivation and bradycardia after pesticide spraying. Which result supports organophosphate poisoning?

Answer: C. Decreased red cell acetylcholinesterase activity

Organophosphates irreversibly inhibit acetylcholinesterase (and serum butyrylcholinesterase), so acetylcholine accumulates. Red cell AChE best reflects inhibition at nerve synapses.

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Q105MediumEnzymes & cardiac markers

Serum tartrate-resistant acid phosphatase isoform 5b (TRAP 5b) is a marker of:

Answer: D. Osteoclastic bone resorption

TRAP 5b is secreted by osteoclasts and reflects bone resorption. Prostatic acid phosphatase is inhibited by tartrate. Bone ALP is a marker of osteoblast (formation) activity.

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Q106MediumEnzymes & cardiac markers

LD-1, the fastest-migrating lactate dehydrogenase isoenzyme, is composed of:

Answer: B. Four H subunits

LD is a tetramer of H (heart) and M (muscle) subunits. LD-1 is H4, found in heart, red cells and kidney; LD-5 is M4, found in liver and skeletal muscle.

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Q107MediumEnzymes & cardiac markers

In the lactate-to-pyruvate (forward) LD method, enzyme activity is measured as:

Answer: D. An increase in absorbance at 340 nm as NAD+ is reduced to NADH

Lactate + NAD+ → pyruvate + NADH; NADH absorbs at 340 nm, so absorbance rises. The reverse (pyruvate-to-lactate) method measures a fall in NADH absorbance.

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Q108MediumEnzymes & cardiac markers

Under the revised Atlanta classification, which enzyme result counts as one criterion for acute pancreatitis?

Answer: C. Lipase or amylase at least 3 times the upper limit

Two of three are needed: typical abdominal pain, lipase or amylase at least 3 × URL, and typical imaging findings. Smaller rises occur in many non-pancreatic conditions.

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Q109MediumEnzymes & cardiac markers

A woman with fatigue, weight gain and cold intolerance has CK 900 U/L with normal troponin. She has no recent exercise, injury or injections. Which test is most useful next?

Answer: C. Thyroid-stimulating hormone

Hypothyroidism causes a myopathy with raised CK, often with these symptoms. TSH is needed before investigating for primary muscle disease. Normal troponin makes a cardiac cause unlikely.

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Q110MediumEnzymes & cardiac markers

A patient arrives 1 hour after chest pain began. The first high-sensitivity troponin is within the reference range. What is the correct next step?

Answer: B. Repeat troponin after a set interval to look for a rise

Troponin may not yet be raised soon after symptom onset. Serial measurements are needed to detect a rise and/or fall that confirms myocardial injury.

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Q111MediumEnzymes & cardiac markers

Enzyme A has a Km of 0.1 mmol/L and enzyme B has a Km of 5 mmol/L for the same substrate. Which statement is correct?

Answer: C. Enzyme A has the higher affinity for the substrate

Km is the substrate concentration at half-maximal velocity. A lower Km means half-maximal rate is reached at a lower substrate level, indicating higher affinity.

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Q112MediumEnzymes & cardiac markers

A 5-year-old boy has progressive leg weakness and difficulty climbing stairs. Serum CK is 15,000 U/L. Which condition is most likely?

Answer: D. Duchenne muscular dystrophy

Duchenne muscular dystrophy causes very high serum CK (often more than 10 times normal) from early childhood because of ongoing skeletal muscle damage.

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Q113HardEnzymes & cardiac markers

On a Lineweaver–Burk plot, lines with and without an inhibitor meet on the y-axis. The inhibitor is:

Answer: C. Competitive

Same y-intercept means unchanged Vmax, while a steeper slope shows raised apparent Km, which is competitive inhibition. Non-competitive lines meet on the x-axis; uncompetitive lines are parallel.

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Q114HardEnzymes & cardiac markers

Why do IFCC reference methods add pyridoxal-5′-phosphate to ALT and AST assays?

Answer: D. To activate apoenzyme lacking its coenzyme

Transaminases need PLP; in patients with low B6 some enzyme circulates as inactive apoenzyme, so adding PLP avoids underestimating activity. Substrates are the amino acids and α-ketoglutarate.

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Q115HardEnzymes & cardiac markers

In metabolic control analysis, which parameter shows how much pathway flux changes when one enzyme's concentration changes?

Answer: A. Flux control coefficient

The flux control coefficient links fractional change in flux to fractional change in enzyme amount. Elasticity describes an enzyme's sensitivity to a metabolite.

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Q116HardEnzymes & cardiac markers

In metabolic control analysis, which term describes how sensitive one enzyme's rate is to the concentration of a metabolite?

Answer: D. Elasticity coefficient

The elasticity coefficient is a local property of one enzyme. The flux control coefficient is a system property describing the whole pathway.

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Q117HardEnzymes & cardiac markers

Making sphingosine from serine and palmitoyl-CoA needs several cofactors. Which one is NOT used?

Answer: A. NAD+

PLP-dependent serine palmitoyltransferase starts the pathway. NADPH reduces 3-ketosphinganine, and an FAD-linked desaturase adds the double bond at the ceramide stage.

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Q118HardEnzymes & cardiac markers

On a Lineweaver–Burk plot, a noncompetitive inhibitor changes which value?

Answer: D. The y-intercept (1/Vmax), with the same x-intercept

A noncompetitive inhibitor binds outside the active site and lowers Vmax, raising 1/Vmax (y-intercept) while Km stays the same. An unchanged y-intercept is the pattern for competitive inhibition.

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Q119HardEnzymes & cardiac markers

Total CK is 5000 U/L and CK-MB is 40 U/L. What is the relative index, and the likely source?

Answer: A. 0.8%, skeletal muscle

Relative index = CK-MB ÷ total CK × 100 = 40 ÷ 5000 × 100 = 0.8%. Values below about 2.5–3% point to a skeletal muscle source despite a raised CK-MB.

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Q120HardEnzymes & cardiac markers

Diadenosine pentaphosphate and AMP are added to CK reagents to:

Answer: B. Inhibit adenylate kinase released from red cells

Adenylate kinase from red cells or platelets also forms ATP and would falsely raise CK; these inhibitors block it. Sulfhydryl protection is the role of N-acetylcysteine.

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